SOLUTION
Step1: write out the formula for the probability of an event E
[tex]\begin{gathered} Pr(E)=\frac{required\text{ outcome }}{Total\text{ possible outcome}} \\ \\ \text{Total possible of a die is 6} \end{gathered}[/tex]Step2: Write out the parameters
[tex]\begin{gathered} \text{probability of obtaining 3 is } \\ Pr(3)=\frac{1}{6} \end{gathered}[/tex]Then
[tex]\begin{gathered} \text{Probability of obtaining 5} \\ Pr(5)=\frac{1}{6} \end{gathered}[/tex]The probability that the roll of a die will show 3 or 5 is
[tex]\begin{gathered} Pr(3)+Pr(5) \\ \frac{1}{6}+\frac{1}{6} \\ \frac{2}{6}=\frac{1}{3} \end{gathered}[/tex]The probability that the roll of a die will show 3 or 5 is 1/3
The right option is B
