The composite figure is made by: 2 right triangles and 1 semicircle. Or 1 triangle and 1 semicircle. With any of the two combinations of shapes the area is the same.
To find the area you sum the area of each shape that compose the figure:
1 triangle and 1 semicircle:
[tex]\begin{gathered} A=A_{\Delta}+A_s \\ \\ A=\frac{1}{2}b\cdot h+\frac{1}{2}\pi\cdot r^2 \end{gathered}[/tex]
As the given figure has the diameter of the circle you find the radius as follow:
[tex]\begin{gathered} r=\frac{d}{2} \\ r=\frac{14m}{2} \\ r=7m \end{gathered}[/tex]
The base of the triangle is 14m and the height is 10m.
[tex]\begin{gathered} A=\frac{1}{2}(14m)(10m)+\frac{1}{2}\pi(7m)^2 \\ \\ A=\frac{140}{2}m^2+\frac{49\pi}{2}m^2 \\ \\ A=70m^2+76.97m^2 \\ \\ A=146.97m^2 \end{gathered}[/tex]
The area of the composite figure is 146.97 square meters
