We must first assume that the base of the cone and the cylinder hvae tha same base shape and size.
The volumen of a cone is equal to one third of the volumen of the cylinder, whose base and height are equal those of the cone:
Therefore:
[tex]V_{\text{cone}}=\frac{1}{3}V_{cylinder}[/tex]replacing:
[tex]\begin{gathered} 5=\frac{1}{3}V_{cylinder} \\ V_{cylinder}=5\cdot3 \\ V_{cylinder}=15 \end{gathered}[/tex]The answer is 15 in^3
