Respuesta :
Given data
*The given wavelength of the ultraviolet light is
[tex]\lambda=182nm=182\times10^{-9}\text{ m}[/tex]*The given total energy is E_t = 1.28 × 10^-13 J
The formula for the difference in energy between the two levels that participate in stimulated emission in the excimer laser is given as
[tex]\Delta E=\frac{hc}{\lambda}[/tex]*Here h = 6.626 × 10^-34 J.s is the Planck's constant.
*Here c = 3.0 × 10^8 m/s is the speed of the light.
Substitute the known values in the above expression as
[tex]\begin{gathered} \Delta E=\frac{(6.626\times10^{-34})(3.0\times10^8)}{(182\times10^{-9})} \\ =0.109\times10^{-17}\text{ J} \end{gathered}[/tex]Hence, the difference in energy between the two levels that participate in stimulated emission in the excimer laser is 0.109 × 10^-17 J
The number of photons from this laser is required to deliver energy is calculated as
[tex]\begin{gathered} E_t=n\Delta E \\ n=\frac{E_t}{\Delta E} \\ =\frac{1.28\times10^{-13}}{0.109\times10^{-17}} \\ =\text{1}.17\times10^5\text{ photons} \end{gathered}[/tex]Hence, the number of photons from this laser is required to deliver energy is n = 1.17 × 10^5 photons
