ANSWER:
1st option: 70 cm
STEP-BY-STEP EXPLANATION:
Given:
Force (F) = 5.73 E−1 N^
Electrical charge 1 (q1) = 1.2 E−5 C
Electrical charge 2 (q2) = 2.5 E−6 C
k = 8.99 E9 N*m2/C2
We can calculate the distance between both charges with the help of Coulumb's law, just like this:
[tex]F=k\cdot\frac{q_1\cdot q_1}{d^2}[/tex]We substitute and solve for the distance, just like this:
[tex]\begin{gathered} 5.73\cdot\: 10^{-1}=\frac{8.99\cdot10^9\cdot\:1.2\cdot\:10^{-5}\cdot2.5\cdot10^{-6}}{d^2} \\ d^2=\frac{8.99\cdot10^9\cdot1.2\cdot10^{-5}\cdot2.5\cdot10^{-6}}{5.73\cdot10^{-1}} \\ d=\sqrt[]{0.47} \\ d=0.69\text{ m}\cong0.70\text{ m}=70cm \end{gathered}[/tex]The distance is 70 centimeters
