Solution:
Given:
A cone and a triangular pyramid.
The cone has a circular cross-section and the pyramid has a triangular cross-section.
For the cone, the cross-section is circle 1.
Circle 1 has the following property;
[tex]\begin{gathered} r=12 \\ \\ \text{Area of a circle is gotten by;} \\ A=\pi r^2 \\ A=\pi\times12^2 \\ A=144\pi\text{units}^2 \end{gathered}[/tex]
For the pyramid, the cross-section is triangle 1.
Triangle 1 has the following properties;
[tex]\begin{gathered} b=24 \\ h=12\pi \\ \\ \text{Area of a triangle is gotten by;} \\ A=\frac{1}{2}bh \\ A=\frac{1}{2}\times24\times12\pi \\ A=144\pi\text{units}^2 \end{gathered}[/tex]
Therefore, the solution is;
