Respuesta :
The two points on the line is (0,-1) and (3,-6).
Use the slope intersept form to calculate the equation of the line.
[tex]y-y1=\frac{y2-y1}{x2-x1}(x-x1)[/tex]Put these points in the equation implies,
[tex]\begin{gathered} y+1=\frac{-6+1}{3-0}(x-0) \\ y+1=\frac{-5}{3}x \\ 3y+3=-5x \\ 3y+5x+3=0 \end{gathered}[/tex]Therefore, the equation of the line is 3y+5x+3=0.
Consider the second line, the points are (0,-2) and (1,0).
[tex]\begin{gathered} y+2=\frac{0+2}{1-0}x \\ y+2=2x \\ y=2x-2 \end{gathered}[/tex]Thus, the equation of the line is y=2x-2.
Consider the third line, the points are (0,1) and (-3,6).
[tex]\begin{gathered} y-1=\frac{6-1}{-3-0}x \\ y-1=-\frac{5}{3}x \\ y=-\frac{5}{3}x+1 \end{gathered}[/tex]Thus, the equation of the line is y=-(5/3)x+1.
