Given
n = 2000
p = 13% = 0.13
margin of error = 4% = 0.04
Find
If the confidence level is 90% what is the value of a.
Explanation
From the given information ,
p = 0.13
q = 1 - 0.13 = 0.87
margin of error = 0.04
confidence level = 90% = 0.90
[tex]\begin{gathered} \alpha=1-0.90 \\ \alpha=0.10 \end{gathered}[/tex]
Final Answer
Hence , the value is 0.10
