Data Input
P = 7000
r = 4.6%
t = 10 years
Procedure
The population after 10 years can be found by
[tex]\begin{gathered} P=P_o(1+\frac{t}{100})^t \\ \end{gathered}[/tex]where
P is the population after 10 years
t is the times
r is the rate of interest
Po is the initial population
[tex]\begin{gathered} P(t)=7000(1+\frac{4.6}{100})^{10} \\ P(t)=7000(1+0.046)^{10} \\ P(t)=7000(1.046)^{10} \\ P(t)=10975 \end{gathered}[/tex]The population would be 10975
