first we find the slope with this formula
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where the point(x2,y2) is the rightmost point between the two points
so, for this case (x2,y2)=(4,8) and (x1,y1)=(3,4)
[tex]\begin{gathered} m=\frac{8-4}{4-3} \\ m=\frac{4}{1} \\ m=4 \end{gathered}[/tex]and the general equation of a line is
[tex]y=mx+b[/tex]we can find b replace the points(x,y) with any point of the line, example (3,4)
[tex]\begin{gathered} (4)=(4)(3)+b \\ 4=12+b \\ b=-8 \end{gathered}[/tex]next, make the equation with b and m
[tex]y=4x-8[/tex]you can replace a point to chek
[tex]\begin{gathered} (8)=4(4)-8 \\ 8=16-8 \\ 8=8 \end{gathered}[/tex]so, correct
