Respuesta :
Data:
Sonic boom: b
Light: l
[tex]\begin{gathered} b=1.2x10^9\frac{m}{s} \\ \\ l=3.0x10^8\frac{m}{s} \end{gathered}[/tex]To find how many times faster is the speed of light of the sonic boom than the speed of light you:
-Divide the speed of sonic boom into speed of light:
[tex]\frac{1.2x10^9}{3.0x10^8}[/tex]In scientific notation you divide the coefficients as normal and substract the power in denominator from the power in the numerator:
[tex]\begin{gathered} =\frac{1.2}{3.0}x10^{9-8} \\ \\ =0.4x10^1=4 \end{gathered}[/tex]Then, the speed of the sonic boom is 4 times faster than the speed of the light.--------------As the sonic boom is sent by the sun, and you are in the sun. You only need the laser to be in each planet 1 thousand of a second before the sonic boom.
Then, the speed of the laser needs to be:
Calculate the meters that the sonic boom travels in 0.001 seconds:
[tex]1.2x10^9\frac{m}{s}\cdot(0.001s)=1.2x10^6m[/tex]As in 0.001 secons the sonic boom travels 1.2x10 6 m, the laser needs to travel this quantity plus the quantity that the sonic boom travels in a second.
[tex]\begin{gathered} 1.2x10^9m+1.2x10^6m \\ =1.2x10^6m+0.0012x10^9m \\ \\ =1.2012x10^9m \end{gathered}[/tex]As the laser needs to travel this distance in a second, the speed (s) of the laser needs to be:[tex]s=1.2012x10^9\frac{m}{s}[/tex]