[tex]A_{shaded}=\frac{275\pi}{4}\approx215.98449u²\approx216u²[/tex]
1) Considering the line segment AC to be the diameter, then we can state the following:
Assuming point E is in the center of the circle.
2) So now, let's find the area of these identical sectors:
[tex]\begin{gathered} A=\frac{55}{360}\cdot\pi\cdot15^2 \\ A=\frac{275}{8}\pi \\ A_{Shaded}=\frac{275}{8}\pi+\frac{275}{8}\pi=\frac{275}{4}\pi \end{gathered}[/tex]
