ANSWER
[tex]200,000N\/m^2[/tex]
EXPLANATION
Parameters given:
Moment of weight about the pivot, m = 12 Nm
Perpendicular distance, d = 0.2 m
Area of the piston, A = 0.0003 m²
To find the minimum pressure for the steam to escape, we have to apply the equation for pressure:
[tex]P=\frac{F}{A}[/tex]
where F = force, A = area of the surface on which the force is applied
First, we have to find the force that will be applied by the steam using the moment equation:
[tex]\begin{gathered} m=F\cdot d \\ \Rightarrow F=\frac{m}{d} \end{gathered}[/tex]
Therefore, the force is:
[tex]\begin{gathered} F=\frac{12}{0.2} \\ F=60N \end{gathered}[/tex]
Hence, the minimum pressure for the steam to escape is:
[tex]\begin{gathered} P=\frac{60}{0.0003} \\ P=200,000N\/m^2 \end{gathered}[/tex]
