The point slope form of the equation of a line is
[tex]y-y_1=m(x_{}-x_1)[/tex]where (x1,y1) is the point that the line passes through and m is the slope.
Using the values given, we have
[tex]\begin{gathered} y-6=-\frac{3}{4}(x-(-4)) \\ y-6=-\frac{3}{4}(x+4) \end{gathered}[/tex]Therefore the equation written in the point slope form is
[tex]y-6=-\frac{3}{4}(x+4)[/tex]