Given
A fair die is rolled three times. What is the probability of obtaining no 5’s
Solution
[tex]\begin{gathered} \text{Probability of obtaining 5 =}\frac{1}{6} \\ \therefore\text{Probability of obtaining 5 in thre}eroll\text{ =}\frac{5}{6}\times\frac{5}{6}\times\frac{5}{6}=\frac{125}{216} \\ \end{gathered}[/tex]
The final answer
A fair die is rolled three times, the probability of obtaining no 5’s is
[tex]\frac{125}{216}[/tex]