In order to determine the initial termperature of the acetone, consider it as an idel gas. Then, you can write the following relation between volumes and temperatures:
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]In this case, consider that the pressure is constant, then, P1=P2=P.
You cancel out pressure from the previous equation, solve for T1 and replace the values of the other parameters, as follow:
[tex]\begin{gathered} T_1=T_2\frac{V_1}{V_2} \\ T_1=(72C)(\frac{180L}{210L}) \\ T_1\approx61.7C \end{gathered}[/tex]Hence, the initial temperature of the acetone was approximately 61.7°C
