Taking the given equation to its slope-intercept form we get:
[tex]\begin{gathered} y-10=60x-2400, \\ y=60x-2400+10, \\ y=60x-2390. \end{gathered}[/tex]
Therefore, the slope of the line is 60.
Now, when x=40:
[tex]y=60\times40-2390=10.[/tex]
Therefore the point (40,10) is on the line.
Answer: The point (40,10) is on the line, and the slope of the line is 60.
