Given data
*The given acceleration is a = 0.62 m/s^2
*The given time is t = 90 s
*The initial velocity of the parked motorcycle is u = 0 m/s
The formula for the final velocity of the motorcycle is given by the equation of motion as
[tex]v=u+at[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} v=(0)+(0.62)(90) \\ =55.8\text{ m/s} \end{gathered}[/tex]Hence, the final velocity of the parked motorcycle is v = 55.8 m/s
