B) y=11.42x
Explanation
Step 1
Let
[tex]\begin{gathered} y=f(x) \\ f(x)=11.20\text{ x} \end{gathered}[/tex]If the race had been run a few minutes earlier when there was a tailwind, it is estimated that her speed would have been 1.02 times the speed
[tex]\text{speed}=\text{ }\frac{dis\tan ce\text{ }}{\text{time}}=\frac{y}{x}=\frac{11.20x}{x}=11.20[/tex]then
[tex]\begin{gathered} new\text{ speed = old speed}\cdot1.02 \\ \text{new speed=1.02}\cdot11.20=11.42 \end{gathered}[/tex]so, the answer is
[tex]B)y=11.42x[/tex]