Respuesta :
Answer:
The percent yield is 77.18%.
Explanation:
1st) According to the balanced reaction, 1 mole of Pb(NO3)2 reacts with 2 moles of KI to produce 2 moles of KNO3 and 1 mole of PbI2.
We can convert the moles to grams using the molar mass of Pb(NO3)2 (331.2g/mol), KI (166g/mol) and KNO3 (101g/mol):
- Pb(NO3)2 conversion: 331.2g
- KI conversion: 332g
- KNO3 conversion: 202g
2nd) Now, with the stoichiometry of the reaction in grams we can calculate the grams of KNO3 that must be produced (this is the Theoretical yield):
[tex]\begin{gathered} 332gKI-202gKNO_3 \\ 32.92gKI-x=\frac{32.92gKI*202gKNO_3}{332gKI} \\ x=20.03gKNO_3 \end{gathered}[/tex]So, this is the theoretical amount of KNO3.
3rd) With the theoretical yield (20.03g) and the Actual yield (15.46g) we can calculate the percent tield:
[tex]\begin{gathered} \text{ Percent yield=}\frac{\text{ Actual yield}}{\text{ Theoretical yield}}*100 \\ \text{ Percent yield=}\frac{15.46g}{20.03g}*100 \\ \text{ Percent yield=77.18\%} \end{gathered}[/tex]So, the percent yield is 77.18%.
