In a pet store
There are 8 puppies, 10 kittens and 6 parakeets.
The total number of pets, i.e total outcome is
[tex]8+10+6=24[/tex]Let P represent puppies
Let K represent kittens and
Let Pa represent parakeets
The formula to find probability is
[tex]\text{Probability}=\frac{\text{required outcome}}{total\text{ outcome}}[/tex]The probability of choosing a puppy, i.e P(P) is
[tex]\begin{gathered} P(P)=\frac{\text{required outcome}}{total\text{ outcome}}=\frac{8}{24}=\frac{1}{3} \\ P(P)=\frac{1}{3} \end{gathered}[/tex]The probability of choosing a kitten, i.e P(K) is
[tex]P(K)=\frac{\text{required outcome}}{total\text{ outcome}}=\frac{10}{24}=\frac{5}{12}[/tex]The probability of choosing a puppy or a kitten, P(P or K) is
[tex]\begin{gathered} P(P\text{ or K)}=P(P)+P(K)=\frac{1}{3}+\frac{5}{12} \\ P(P\text{ or K)}=\frac{4+5}{12}=\frac{9}{12}=\frac{3}{4} \\ P(P\text{ or K)}=\frac{3}{4} \end{gathered}[/tex]The probability of choosing a puppy or a kitten, P(P or K) is 3/4
Hence, the right option is B
