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Please help meGiven a triangle ABC, AM = 2/3 * AB, AN = 3/2 * AC. Line MN intersects BC at point K. Find coordinates of vector AK in basis from vector AB and AC..

Respuesta :

[tex]\begin{gathered} AM=\frac{2}{3}AB \\ AN=\frac{3}{2}AC \end{gathered}[/tex][tex]\begin{gathered} MN=MK+NK\to(1) \\ MN=AM+AN\to(2) \\ MN=NK+AK+AM\to(3) \\ AN=AK+NK\to(4) \end{gathered}[/tex][tex]\begin{gathered} NK=AN-AK\to(4) \\ MN=(AN-AK)+AK+AM \end{gathered}[/tex]

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