According to the equation of line:
[tex]y-y_1=m(x-x_1)[/tex]As given that slope is 0 so put the point and slope in formula:
[tex]\begin{gathered} y-\frac{3}{10}=0(x-0) \\ y-\frac{3}{10}=0 \\ y=\frac{3}{10} \end{gathered}[/tex]So it is the required line .
[tex]y=\frac{3}{10}[/tex]This is the equation of line.
