So we need to evaluate this expression:
[tex]-x^2-4y+6x[/tex]
In x=-2 and y=3. So we just need to replace x and y with -2 and 3:
[tex]\begin{gathered} -x^2-4y+6x=-(-2)^2-4\cdot3+6\cdot(-2) \\ -(-2)^2-4\cdot3+6\cdot(-2)=-(-2)\cdot(-2)-12-12 \\ -(-2)\cdot(-2)-12-12=-4-12-12=-28 \end{gathered}[/tex]
Then the answer is -28.
