Respuesta :
There are 5 vowels and 10 of them with a vowel (5 uppercase and 5 lower case).
Now, we know that Jenny selected a vowel on her first draw, so there are 51 cards and 9 of them are vowel. Therefore, the probability that Jenny selects a vowel in a second draw is given by
[tex]P(\text{ Jenny selects a vowel in the 2nd draw) =}\frac{9}{51}=0.1764[/tex]and there are 50 cards and 8 of them are vowels
On the other hand, if Jenny selected a vowel on her first draw but she replace the card, there are 52 cards again (10 of them are vowels). So, the probability that Jenny slects a vowel in the second draw is given by
[tex]P(\text{ Jenny selects a vowel in the 2nd draw) =}\frac{10}{52}=0.1923[/tex]because the total number of cards doesn't change.
In summary, the answers are:
What is the probability that she selects a vowel, if on the first draw Jenny selects a vowel and does not replace it? Answer:
[tex]\frac{9}{51}=0.18[/tex]How many cards remain, and how many are vowels? Answer: It remains 50 cards and 8 of them are vowels.
If she selected a vowel on her first draw without replacement, What is the probability she selects a vowel on her second draw? Answer:
[tex]\frac{10}{52}=0.19[/tex](
