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Which counterexample shows that the following conjecture is false? Every perfect square number has exactly three factors. F The factors of 2 are 1, 2.G The factors of 4 are 1, 2, 4, H The factors of 8 are 1,2,4,8,I The factors of 16 are 1, 2, 4, 8, 16,

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hello

from the options given,

G and I are perfect squares with the exception of F and H

F is not a perfect square which is the perfect square of 2

G is a perfect square and it's the perfect square of 2

H is not a perfect square

I is a perfect square and it is the perfect square of 16

the answer to this question is I

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