A sprinkler rotates back and forth from point A to point B. The water reaches 8 meters from the base of the sprinkler. What is the length of the arc AB, rounded to the nearest tenth of a meter? Use 3.14 for it pi.

Length of the given arc can be given as,
[tex]\begin{gathered} l=r\theta \\ l=8\times150\times\frac{\pi}{180} \\ l=\frac{8\times15\times\pi}{18} \\ l=20.94 \end{gathered}[/tex]Hence, option D is correct.