Solution:
If the bigger square has a perimeter of 36 in, then the side length is:
[tex]\frac{36}{4}=\text{ 9}[/tex]
thus, the area of the bigger square is:
[tex]A_1\text{ = 9x9 = 81}[/tex]
on the other hand, the area of the smallest square would be:
[tex]A_2\text{ = 4 x 4 = 16}[/tex]
so that, the ratio of the areas of the larger square to the smallest square is:
[tex]\frac{A_1}{A_2}\text{ = }\frac{81}{16}\text{= 5.06}[/tex]
then, the correct answer is:
[tex]\text{ }\frac{81}{16}\text{= 5.06}[/tex]
