identify points of discontinuity and classify the type of each discontinuity

Infinite discontinuity
Explanations:The given equation is:
[tex]y\text{ = }\frac{2x}{x+1}[/tex]The function will be undefined at the point x + 1 = 0
x = -1
This means that x = -1 is a point of discontinuity
Substituting x = -1 into the equation:
[tex]\begin{gathered} y\text{ = }\frac{2(-1)}{-1+1} \\ y\text{ = }\frac{-2}{0} \\ y\text{ = }\infty \end{gathered}[/tex]This is an infinite discontinuity