ANSWER:
[tex]m+\frac{m-11}{m-8}[/tex]
STEP-BY-STEP EXPLANATION:
We have the following division
[tex]\begin{gathered} (m^2-7m-11)\div(m-8) \\ \text{what is equal to:} \\ \frac{m^2-7m-11}{m-8} \end{gathered}[/tex]
Now we carry out the operation and we have:
We divide the quotients of the higher degree terms of the numerator and the divisor
[tex]\frac{m^2}{m}=m[/tex]
Then we multiply this quotient by the denominator
[tex]m\cdot(m-8)=m^2-8m[/tex]
Now, we subtract this value from the numerator and we have
[tex]\begin{gathered} m^2-7m-11-(m^2-8m)=m^2-7m-11-m^2+8m=m-11 \\ \end{gathered}[/tex]
Therefore the final result would be
[tex]\frac{m^2-7m-11}{m-8}=m+\frac{m-11}{m-8}[/tex]
