Explanation:
Part C
The question wants us to get the measurement of the angle formed between the line segments.
We are also told that the line segment is also the slant height
Thus
So we will have to find the angle at C
So, the scope will be to find the half-angle and then multiply by 2
Thus, we will have
Thus, we will have
[tex]tan(\frac{\theta}{2})=\frac{opposiste}{adjacent}=\frac{2}{6}=\frac{1}{3}[/tex]
Thus
[tex]\begin{gathered} \frac{\theta}{2}=\tan^{-1}(\frac{1}{3}) \\ \frac{\theta}{2}=18.435 \end{gathered}[/tex]
Thus, we will have to get the measurement of the angle as
[tex]2\times(\frac{\theta}{2})=2\times18.435[/tex]
Thus, we have the angle to be 36.87 degrees
