3.53moles
The formula for calculatung the moles of the compound is expressed as:
[tex]moles\text{ of CCl}_4=\frac{mass}{molar\text{ mass}}[/tex]Given the following
Mass of CCl4 = 543.2 grams
Determine the molar mass of CCl4
[tex]\begin{gathered} molar\text{ mass}=12.01+4(35.45) \\ molar\text{ mass}=12.01+141.8 \\ molar\text{ mass}=153.81gmol^{-1} \end{gathered}[/tex]Determine the required mole
[tex]\begin{gathered} mole\text{ of CCl}_4=\frac{543.2}{153.81} \\ mole\text{ of CCl}_4=3.53moles \end{gathered}[/tex]Hence the moles of tetrachloride is 3.53moles