If log2(7x+4) =2 you may enter value or round to 4 decimal place

Okay, here we have this:
Considering the provided equation, we are going to solve it, so we obtain the following:
[tex]\begin{gathered} log_2(7x+4)=2 \\ 7x+4=2^2 \\ 7x+4=4 \\ 7x=4-4 \\ 7x=0 \\ x=\frac{0}{7} \\ x=0 \end{gathered}[/tex]Finally we obtain that x is equal to 0.