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29-10-2022
Mathematics

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Find the area to the right of x=60 under a normal distribution curve with the mean=71 and standard deviation=6.

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OliveV68127 OliveV68127

29-10-2022

Given that:

Mean = 71

Standard deviation = 6

To find

[tex]P(X>60)[/tex]

The Z-score for X is

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

Thus,

[tex]\begin{gathered} P(X>60)=P(Z>\frac{60-71}{6}) \\ =P(Z>-1.83) \\ =0.5+P(0From the standard normal table, P(0

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