Given data:
The current is I=14.72 A.
The time taken is t=22.94 s.
The charge pass through the wire can be calculated as,
[tex]\begin{gathered} Q=It \\ Q=(14.72)(22.94) \\ Q=337.6\text{ C} \end{gathered}[/tex]If the charge on an electron is e=1.6x10⁻¹⁹ C, the the number of electrons pass through the wire will be,
[tex]\begin{gathered} n=\frac{Q}{e} \\ n=\frac{337.6}{1.6\times10^{-19}} \\ n=211\times10^{19} \end{gathered}[/tex]Thus, the number of electrons pass through the wire in 22.94 s is 211x10¹⁹.
Final Answer: 211x10¹⁹
