The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Where
(h, k) is the center
r is the radius
Given,
Center (1, 2) and Radius 5, we can write >>>
[tex](x-1)^2+(y-2)^2=5^2[/tex]
This is the equation of the circle. We plug in each point (x, y) into the circle equation and see which one does not satisfy the equation.
Checking (4, 6)
[tex]\begin{gathered} (4-1)^2+(6-2)^2\stackrel{?}{=}5^2 \\ 9+16\stackrel{?}{=25} \\ 25=25 \end{gathered}[/tex]
Checking (-2, -2)
[tex]\begin{gathered} (-2-1)^2+(-2-2)^2\stackrel{?}{=}5^2 \\ 9+16\stackrel{?}{=}25 \\ 25=25 \end{gathered}[/tex]
Checking (1, 6)
[tex]\begin{gathered} (1-1)^2+(6-2)^2\stackrel{?}{=}5^2 \\ 0+16\stackrel{?}{=}25 \\ 16\neq25 \end{gathered}[/tex]
So, the point (1, 6) doesn't lie on the circle!
