As given by the question
There are given that the right angle triangle
Now,
From the triangle, first, find the value of ST
So,
To find the value of ST, use the sine function
Then,
[tex]\sin 30^{\circ}=\frac{ST}{RT}[/tex]
Then,
[tex]\begin{gathered} \sin 30^{\circ}=\frac{ST}{RT} \\ \frac{1}{2}^{}=\frac{ST}{12} \\ 2\times ST=12 \\ ST=\frac{12}{2} \\ ST=6 \end{gathered}[/tex]
Now,
To find the value of RS, use sine function also
So,
[tex]\begin{gathered} \sin 60=\frac{RS}{RT} \\ \frac{\sqrt[]{3}}{2}=\frac{RS}{12} \\ 2\times RS=12\times\sqrt[]{3} \\ RS=\frac{12\times\sqrt[]{3}}{2} \\ RS=6\sqrt[]{3} \end{gathered}[/tex]
Hence, the value of ST and RS is shown below:
[tex]undefined[/tex]
