We know that
• The initial speed is null because Mr. Pierce accelerates from rest.
,• The final speed is 21.1 m/s.
,• The distance traveled is 27.4 meters.
To find the acceleration, we use a formula that relates initial speed, final speed, acceleration, and distance.
[tex]v^2_f=v^2_0+2ad[/tex]Let's use the given magnitudes and solve for a.
[tex]\begin{gathered} (21.1\cdot\frac{m}{s})^2=0^2+2a(27.4m) \\ 445.21\cdot\frac{m^2}{s^2}=54.8m\cdot a \\ a=\frac{445.21\cdot\frac{m^2}{s^2}}{54.8m} \\ a\approx8.12\cdot\frac{m}{s^2} \end{gathered}[/tex]