Therefore,
[tex]\begin{gathered} 2x+3=2x^2+2x+1 \\ 2x^2+2x-2x+1-3=0 \\ 2x^2-2=0 \\ 2(x^2-1)=0 \\ (x-1)(x+1)=0 \\ x=1 \\ or \\ x=-1 \end{gathered}[/tex]substitute the values of x in the equations
[tex]\begin{gathered} y=2(1)+3 \\ y=6 \\ \\ y=2(-1)+3 \\ y=1 \end{gathered}[/tex]Therefore,
(1, 6) (-1, 1)
