Remember that the volume of a cone is:
[tex]V=\frac{1}{3}\pi r^2h[/tex]
Where:
• r ,is the radius of the base
,
• h, is the height of the cone.
Using this formula and the data given, we'll get that:
[tex]\begin{gathered} V=\frac{1}{3}\pi(3^2)(5) \\ \rightarrow V=15\pi \end{gathered}[/tex]
The volume of the cone is around 47.12 cubic inches (15 pi)
