[tex]\text{lenght of wire = }\frac{opposite\text{ side}}{\sin\text{ angle}}\text{ = }\frac{35}{\sin\text{ 45\degree}}\text{ =}\frac{35}{\frac{\sqrt[]{2}}{2}}\text{ = 35}\sqrt[]{2}[/tex][tex]\sin \text{ 45\degree=}\frac{\sqrt[]{2}}{2}[/tex]
[tex]\text{Answer = 35}\sqrt[]{2}\text{ ft}[/tex]
