Given:
[tex]x^3-x^2+4x-6=0[/tex]We will use Descartes's rule of signs to identify the nature of the roots of the equation.
The coefficients will be as follows:
+1, -1, +4, -6
As shown therearea 3 changes from (+) to (-) or reverse
So, the number of positive real roots = 2 or 1
