Examine the diagram of circle A, where DB and CB are tangent to circle A at points D and C. Also, DB = 102 + 16 and CB = 52 + 20.D

Given:
DB and CB are the tangent to the circle A.
[tex]\begin{gathered} DB=CB \\ 10x+16=5x+20 \\ 10x-5x=20-16 \\ 5x=4 \\ x=\frac{4}{5} \end{gathered}[/tex]2nd option is the final answer.