Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a diameter of 18 feet and a height of 9 feet. Container B hasa diameter of 16 feet and a height of 11 feet. Container A is full of water and the wateris pumped into Container B until Conainter B is completely full.To the nearest tenth, what is the percent of Container A that is empty after thepumping is complete?

Respuesta :

To answer this question we will use the following formula to compute the volume of a cylinder:

[tex]\text{Volume}=\frac{diameter^2}{4}\cdot\pi\cdot\text{height.}[/tex]

Therefore, the volume of container A is:

[tex]V_A=\frac{(18ft)^2}{4}\cdot\pi\cdot9ft=729\pi ft^3\text{.}[/tex]

The volume of container B is:

[tex]V_B=\frac{(16ft)^2}{4}\cdot\pi\cdot11ft=704\pi ft^3\text{.}[/tex]

Now, after pumping the water, the percent of container A that is empty is:

[tex]\frac{V_B}{V_A}\times100=\frac{704\pi ft^3}{729\pi ft^3}\times100.[/tex]

Simplifying the above result we get:

[tex]\frac{70400}{729}\approx96.6.[/tex]

Answer: 96.6%