2. The graph of the equation y = x2 + 2x – 8 has a minimum at (x,-9).Part A: What is the value of x ?Part B: What is the y-intercept?Part C: Make a table & graph thefunction.

Problem
Solution
Part A
For this case we can do this:
[tex]-9=x^2+2x-8[/tex]And solving for x we got:
[tex]-1=x^2+2x=x(x+2)[/tex]Then the possible solutions for this case is x= -1
Part B
For this case we can do the following:
[tex]0=x^2+2x-8[/tex]And if we factorize we got:
[tex]0=(x+4)(x-2)[/tex]And the x intercepts are:
x=-4 and x=2
And the y intercept is just (0,-8)
Part C
For this case we can do the following:
x y
-4 0
-3 -5
-2 -8
-1 -9
0 -8
1 -5
2 0
3 7
4 16
and the graph would be given by: