Explanation
In four tosses of a coin
The sample space is
There are 16 possible outcomes
The probability for the number of heads is given below
when x = 0
P(x) will be
[tex]P(0)=\frac{1}{16}=0.0625[/tex]
when x =1 means when we have 1 head
[tex]P(1)=\frac{4}{16}=\frac{1}{4}=0.25[/tex]
when x =2
[tex]P(2)=\frac{6}{16}=0.375[/tex]
when x = 3
[tex]P(3)=\frac{4}{16}=\frac{1}{4}=0.25[/tex]
When x =4
[tex]P(4)=\frac{1}{16}=0.0625[/tex]
