If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?48O y - 3 (2)O y = 4g (2)(48)(B)O y--(48)(6)

The phrase y varies directly as x can be understood that y gets bigger when x gets bigger as well, this can be written as,
[tex]\frac{y_1}{x_1}=\frac{y_2}{x_2}[/tex]then, using the point (6,48) find the value when x is 2,
[tex]\frac{48}{6}=\frac{y_2}{2}[/tex]clear for y2,
[tex]y_2=\frac{48}{6}(2)[/tex]Answer:
[tex]y_=\frac{48}{6}(2)[/tex]