Find the equation of the line given that is perpendicular/parallel using the point (8,-3)

SOLUTION
From -8x +6y = 6, make y the subject. This is because equation of a line is given as y = mx +c, where m is the gradient and c is the intercept.
From -8x + 6y = 6
6y = 6 + 8x
6y = 8x + 6 dividing through by 6, we have
[tex]\begin{gathered} y\text{ = }\frac{8}{6}x\text{ + }\frac{6}{6} \\ y\text{ = }\frac{4}{3}x\text{ + 1} \end{gathered}[/tex][tex]undefined[/tex]