Respuesta :
ANSWER:
0.536 mm/s²
STEP-BY-STEP EXPLANATION:
Given:
Solar intensity (I) = 1380 W/m²
Area (A) = 43,318.28 m²
Mass (m) = 743.39 kg
Speed of light (v) = 3*10^8 m/s
We can calculate the pressure using the following formula:
[tex]\begin{gathered} P=\frac{2I}{v} \\ \\ \text{ We replacing} \\ \\ P=\frac{2(1380)}{(3\cdot10^8)} \\ \\ P=\:0.0000092\text{ Pa} \end{gathered}[/tex]We can determine the acceleration knowing the following:
[tex]\begin{gathered} P=\frac{F}{A} \\ \\ F=ma \\ \\ \text{ We replacing:} \\ \\ P=\frac{ma}{A} \\ \\ a=\frac{P\cdot A}{m} \\ \\ \text{ We substitute each value to determine the acceleration:} \\ \\ a=\frac{0.0000092\cdot43318.28}{743.39} \\ \\ a=0.000536\text{ m/s}^2\cdot\frac{1000\text{ mm}}{1\text{ m}} \\ \\ a=0.536\text{ mm/s}^2 \end{gathered}[/tex]The acceleration is equal to 0.536 mm/s²
