Respuesta :

[tex]2(9a+3)-(11a-2)[/tex]

first solve the parenthesis multiplying by each coefficient

[tex]\begin{gathered} (2\times9a)+(2\times3)+(-1\times11a)+(-1\times-2) \\ 18a+6-11a+2 \end{gathered}[/tex]

now group and operate

[tex]\begin{gathered} (18-11)a+(6+2) \\ 7a+8 \end{gathered}[/tex]

the equivalent expression is 7a+8

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